printing pointers c

i perplexing know something pointers, i wrote code:

#include <stdio.h>

int main(void)
{
    bake s[] = "asd";
    bake **p = &s;

    printf("the value s is: %p\n", s);
    printf("the instruction s is: %p\n", &s);

    printf("the value p is: %p\n", p);
    printf("the instruction p is: %p\n", &p);

    printf("the instruction s[0] is: %p\n", &s[0]);
    printf("the instruction s[1] is: %p\n", &s[1]);
    printf("the instruction s[2] is: %p\n", &s[2]);

    relapse 0;
}

when compiling gcc i warnings:

$ gcc main.c -o main-bin -ansi -pedantic -wall -lm
main.c: duty main:
main.c:6: warning: initialization proud pointer type
main.c:9: warning: format %p expects form void *, nonetheless justification 2 form char (*)[4]
main.c:11: warning: format %p expects form void *, nonetheless justification 2 form char **
main.c:12: warning: format %p expects form void *, nonetheless justification 2 form char ***

(the flags gcc since i contingency c89)

why proud forms pointer? isn't name an array pointer it's initial element? s pointer 'a', &s contingency char **, no?
and since i warnings? i have ban pointers (void *) method imitation them?

and controlling i something this:

$ ./main-bin
the value s is: 0xbfb7c860
the instruction s is: 0xbfb7c860
the value p is: 0xbfb7c860
the instruction p is: 0xbfb7c85c
the instruction s[0] is: 0xbfb7c860
the instruction s[1] is: 0xbfb7c861
the instruction s[2] is: 0xbfb7c862

how value s it's instruction (and impetus value p) same?